不用组件来实现StrCat函数的功能
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asp | 发表日期:2008-10-5 20:53:32
really really slow by nature. This sample code uses classes to speed up the process by ten times. Someone recentally came up with a DLL to do this but not all of us can install a DLL on our ISP's web servers so I wrote this easy to use VB Class for handling string concatenation.
code:
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'**************************************
' Name: StrCat - Non DLL version
' Description:ASP's ability to concatena
' ting many strings together is really rea
' lly slow by nature. This sample code use
' s classes to speed up the process by ten
' times. Someone recentally came up with a
' DLL to do this but not all of us can ins
' tall a DLL on our ISP's web servers so I
' wrote this easy to use VB Class for hand
' ling string concatenation.
' By: Kevin Pirkl
'
' Inputs:Public Property Length - To res
' ize the string length. To use it a secon
' d time on another string just set the .L
' ength property to another value or just
' dereference the object and recreate it.
Public Method Add - too add data to the concatenated string.
'
' Assumes:Didnt do much testing except u
' sing it to add together a string of 100,
' 000 characters and it took about 7 secon
' ds which is not bad. If you need to add
' together more than that dont use this. I
' f your catting char strings like "<TR
' >" + whatever then it should be ok.
'
'This code is copyrighted and has ' limited warranties.Please see http://w
' ww.Planet-Source-Code.com/xq/ASP/txtCode
' Id.6342/lngWId.4/qx/vb/scripts/ShowCode.
' htm 'for details. '**************************************
Set X = New strCat' Create an instance of strCat
X.Length = 100001' Change from the default String length of 100,000
str = ""
For I = 1 To X.Length
X.Add("A") '- takes 7 seconds on my computer
'str = str & "A"'- takes 1 minute 7 seconds on my computer
Next
msgBox(Len(X.Value))
X.Length = 101
For I = 1 To X.Length
X.Add("B")
Next
msgBox(Len(X.Value))
Set X = Nothing ' Destroy the instance.
msgBox("Done")
Class strCat
Private IntCntr
Private strArray()
Private intLength
Public Property Get Length
Length = intLength
End Property
Public Property Let Length( ByVal intLen)
intLength = intLen
IntCntr = 0
Redim strArray(1)
strArray(0) = ""
Redim strArray(intLength)
End Property
Public Property Get Value
Value = Join( strArray,"")
End Property
Private Sub Class_Initialize()
IntCntr = 0
Length = 100000
End Sub
Public Function Add( strToAdd)
strArray(IntCntr) = strToAdd
IntCntr= IntCntr + 1
End Function
End Class
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