References and arrays

文章类别：C语言程序设计 | 发表日期:2008-9-24 14:36:49

PROBLEM: ajackson@keck.tamu.edu (Andrew J. Jackson)

I'm inquiring on how to declare a reference to an array of integers


RESPONS: Efim Birger (efim@microware.com)

try this:

typedef int *intp;
int arr[10];
intp& aaa = arr;


RESPONSE: fjh@munta.cs.mu.OZ.AU (Fergus Henderson), 11 Aug 94

This code is illegal. `aaa' is a (non-const) reference to a pointer to int.
`arr' is an array of int, which will be converted to a pointer to int.
The result of that conversion is a temporary.
You are initializing a non-const reference with a temporary, which is illegal.


RESPONSE: admin@rzaix13.uni-hamburg.de (Bernd Eggink)

There is no such thing as a reference to an array.


RESPONSE: fjh@munta.cs.mu.OZ.AU (Fergus Henderson)

There most certainly is.
(An array of references is illegal, but a reference to an array is quite OK.)

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